how do you find the intercepters

Question

how do you find -2y+x=2y-8 im lost

Answer 1

intersepters...at a military aer base

x-2y = 2y-8

4y=x+8

y=(x/4)+2...strate line

maebee yu want weer line hit x or y axis??????????

set x=0 & y=2.....krats kall this the "y-intersept"

Answer 2

Question: Find the intecepts of the straight line -2y+x=2y-8.

1st, let's put the equation into standard form.

-2y+x=2y-8   -- add 2y to both sides

x = 4y - 8     --  divide by 4

(x/4) = y - 2   -- rearrange

y = (x/4) + 2   -- standard form: "y = mx + c", where m is the slope with m = 1/4. and c is the y-intercept

The y-intercept is where the straight line cuts the y-axis, and when the line cuts the y-axis, this is at x = 0.

The x-intercept is where the straight line cuts the x-axis, and when the line cuts the x-axis, this is at y = 0.

With y = (x/4) + 2, and x = 0, then y = 2.

So, y-intercept = 2

With y = (x/4) + 2, and y = 0, then x = -8.

So, x-intercept = -8