x^2dx+y•(x-1)dy=0
in Algebra 2 Answers by Level 12 User (101k points)

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11 Answers

P_=x^2 ,
by Level 12 User (101k points)
Q_=yx-y and Py+Qx=-y
by Level 12 User (101k points)
I.F=1/1-x
by Level 12 User (101k points)
Therefore du_=x^2/1-x dx+ y(x-1)/1-x dy=0
by Level 12 User (101k points)
→ u(x,y)=c
by Level 12 User (101k points)
æu/æy=-y
by Level 12 User (101k points)
→u=w(x)-y^2/2
by Level 12 User (101k points)
æu/æx=x^2/1-x_=w'(x)
by Level 12 User (101k points)
→w={x^2dx/1-x
by Level 12 User (101k points)
Therefore Y=√c+2w
by Level 12 User (101k points)
Where w=2(1-x)-1/2(1-x)^2-lu(1-x)
by Level 12 User (101k points)

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