Establish the identity (Prove that) sinΘcscΘ - sin²Θ= cos²Θ

Prove that . Or establish the identity
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sine*kosekant=sine/sine=1

so yu hav 1-sine^2=kosine^2

or sine^2+kosine^2=1

Thats true bekaus rite triangel...2 short sides^2=diagonal^2

sine=(1 side)/diagonal & kosine=(other side)/diagonal

add squares & yu get x^2 +y^2=diagonal^2
by

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