me assume yu tri tu sae
yu hav a triangel with 1 side=6 & side 2=sqrt(20)...(sqrt(20)=4.472135955)
Infinut ansers for side3, but hav limits
side 3 gotta be < (side1 +side2)...< 6+sqrt(20)
but side3 gotta be long nuf so side3+shortest > other side
Sins 6 > sqrt(20), rule 2 become.... side3+sqrt(20) >6
thus, side3 >6-sqrt(20)