4a^2 + 1/(4a^2) -2 +4a -1/(4a)

Question

I want solution of this question

Answer 1

(4a^(2)+1)/(4a^(2))-2+(4a-1)/(4a)

Multiply each term by a factor of 1 that will equate all the denominators.  In this case, all terms need a denominator of 4a^(2). The ((4a-1))/(4a) expression needs to be multiplied by ((a))/((a)) to make the denominator 4a^(2).
(4a^(2)+1)/(4a^(2))-2*(4a^(2))/(4a^(2))+(4a-1)/(4a)*(a)/(a)

Multiply the expression by a factor of 1 to create the least common denominator (LCD) of 4a^(2).
(4a^(2)+1)/(4a^(2))-(2*4a^(2))/(4a^(2))+(4a-1)/(4a)*(a)/(a)

Multiply 2 by 4a^(2) to get 8a^(2).
(4a^(2)+1)/(4a^(2))-(8a^(2))/(4a^(2))+(4a-1)/(4a)*(a)/(a)

Multiply the expression by a factor of 1 to create the least common denominator (LCD) of 4a^(2).
(4a^(2)+1)/(4a^(2))-(8a^(2))/(4a^(2))+((4a-1)(a))/(4a^(2))

The numerators of expressions that have equal denominators can be combined.  In this case, ((4a^(2)+1))/(4a^(2)) and -((8a^(2)))/(4a^(2)) have the same denominator of 4a^(2), so the numerators can be combined.
((4a^(2)+1)-(8a^(2))+((4a-1)(a)))/(4a^(2))

Simplify the numerator of the expression.
(-a+1)/(4a^(2))