When the length of a rectangle is x inches and the width is y inches, the perimeter is 28 inches. If the length is doubled and the width is tripled, the perimeter becomes 66 inches. Find the length and width of the original rectangle.
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1 Answer

rektangel DONT BE a triangel...rektangel got 4 sides

rim leng=2*(leng+wide), so half-rim=leng+wide=28/2=14

Then yu make box bigger: nu leng=2*old leng, nu wide=3* old wide, nu half-rim=66/2=33

yu the same gi hu asked this same quesshun bout 2 daes ago???????????

leng+wide=14 or wide=14-leng....

2*leng+3*wide=33 become 2*leng+3*(14-leng)=33

(2-3)*leng+42=33

-leng=33-42=-9

leng=9

wide=14-leng=5
by

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