When the length of a rectangle is x inches and the width is y inches, the perimeter is 28 inches. If the legth is doubled and the width is tripled, the perimeter becomes 66 inches. Find the length and width of the original rectangle.
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1 Answer

rektangel, rim-leng=28, so leng+wide=14, thus leng=14-wide

bigger...2*leng+3*wide giv half-rim=33

2*(14-wide)+3*wide=33

28 -2*wide+3*wide=33

wide=33-28=5

leng=14-5=9
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