Height of a Stone

Suppose that a stone is thrown upward with an initial velocity of 44 feet per second (30 miles per hour) and is released 4 feet above the ground. Its height h in feet after t seconds is given by h(t) = -16t 2 + 44t + 4.
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1 Answer

??????????????????? "velosity" ??????????? RONG...thats the SPEED=44 ft/sek

?????????? yu wanna no how hi it go B4 it tern around & come down & hit yu on hed ?????????

How hi=hite yu gotta be wen DROP rok so that it hit ground at speed=44 ft/sek

speed=gt=44 ft/sek...so t=44/32.2=1.366459627 sekonds

distans=integral av speed=(1/2)gt^2=0.5*32.2*1.36646^2

=16.1*1.8672119

=30.06 ft....maebee round that tu 30ft

then add 4 ft
by

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