y=x^4-10x^2+9 solution set in interval notation

solution set in interval notation
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1 Answer

y=x^4 -10x^2 +9=0

let x^2=z & yu hav x^2-10x+9=0

so z=9 or 1

thus x^2=1 or 9

so x=1, -1, 3, -3
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