how do i solve this 2x^2=2x-5

Your answer

1 Answer

2x^2 = 2x - 5

2x^2 - 2x + 5 = 0

use quadratic equation to solve:

_______

x = [-b ± √b²- 4 a c ] / 2a

substitute into the equation:

a = 2, b = -2, c = -5

_______

x = [-(-2) ± √(-2)²- 4*2*(-5) ]

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2*2

_______ __ __

x = [2 ± √(4 + 40 ] 2 ± √44 2(1 ± √11)

------------------- = ------------ = --------------

4 4 4

x = 1 ± √11

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answered Dec 17, 2011 by waltjhall Level 10 User (55.7k points)

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