8y^2=8y-1 how do i solve this

how do i solve this
in Algebra 2 Answers by Level 1 User (680 points)

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1 Answer

8y^2 = 8y - 1

get one side to = 0

8y^2 - 8y +1 = 0

use the quadratic equation to solve them

a = 8, b = -8, c = 1

plug into the equation

                   _______

X = [-b ± √b2 - 4 a c ] / 2a

by Level 10 User (55.7k points)

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