16r^3n-54q^6n

Thequestion needs to be comlety factored. The numbers are raised to the #of n
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The difference of two squares, a^2 - b^2, factorises as (a+b)(a-b).

So, 16r^3n-54q^6n  factorises as [4r^(3n/2) + rt(54)q^(3n)][4r^(3n/2) - rt(54)q^(3n)]
by Level 11 User (81.5k points)

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