how do you solve log1/2^(3x+1)^1/3=-2

solve each equation.
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1 Answer

log(1/2)^kuberoot(3x+1)=-2

kuberoot(3x+1)*log(1/2)=-2

kuberoot(3x+1)=-2 / log(0.5)

=-2/ -0.301029995

=6.64385619

3x+1=kube(6.64385619)=293.2652939

3x=191.2652939

x=97.42176462
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