length of a rectangle is 11 yd more than double the width, area is 63 yd^2. Find the dimensions

Question

The length of a rectangle is 11 yd more than double the width, and the area of the rectangle is 63 yd^2.  Find the dimensions of the rectangle

Answer 1

rektangel...area=leng*wide=63

leng=2*wide+11

area=wide*(2*wide+11)=63

2*wide^2 +11wide -63=0

yuze quadratik equashun

wide=3.5 or -9...yuze 3.5

leng=2*3.5+11=11+7=18

18*3.5=63

Answer 2

The area of a rectangle is 52yd^2, and the lenght of the rectangle is 5 yd less than double the width. Find the dimensions