Verify the equation to see if one side would equal the other.
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2 Answers

kosine*tan=kosine*(sine/kosine)=sine...sine^2/sine

kosine*kotan=kosine*(kosine/sine)=kosine^2/sine

sum=(sine^2 +kosine^2)/sine=1/sine...kosekant
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Prove that,

cos(x)(cot(x)+tan(x)) = csc(x) = 1/sin(x)

manipulate the lhs

cos(x){cos(x)/sin(x) + sin(x)/cos(x)}

cos(x){cos^2(x)/[cos(x)sin(x)] + sin^2(x)/[cos(x)sin(x)]}

cos(x){cos^2(x) + sin^2(x)}/[cos(x)sin(x)]

cos(x){1}/[cos(x)sin(x)]

1/sin(x) = rhs

Q.E.D.

by Level 11 User (81.5k points)

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