4*(3+n)=(4*3)+(4*2)
what is the N value?
4 * (3 + n) = (4 * 3) + (4 * 2)
(4 * 3) + (4 * n) = (4 * 3) + (4 * 2)
First, the (4 * 3) on both sides of the equation cancel out
by subtraction.
(4 * n) = (4 * 2)
Next, the 4 on both sides of the equation cancel out
by division, leaving:
n = 2