4^(x+3)=16^(x-2)

solve for x
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1 Answer

4^(x+3)=16^(x-2)

4^(x + 3) = 4 ^ 2(x - 2)

since they are the same root we can solve for the exponents

x + 3 = 2(x - 2)

x + 3 = 2x - 4

3 = 2x - x - 4

x = -4 - 3

x = -7

by Level 10 User (55.7k points)

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