f(x)=4ke^(x-2)-3 solve for k

Question

x is less than 2 and must make f(x) continuous on (-infinity,+infinity)

Answer 1

y=4k*e^(x-2) -3 . . . . y+3=4k*e^(x-2) . . . (y+3)/4k = e^(x-2) . . . ln[(y+3)/4k] =ln[e^(x-2)].....=x-2 . . . x=2+ln[(y+3)/4k] . . . . ???????? yu sae x gotta be < 2 & then yu sae . . . x is kontinuous tween -infinity tu + infinity . . . ???????? yu hav NE idea wot that meen ?????????