Using the Geometeric formula:

A person deposited \$500 in a savings account that pays 5% annual interest that is compounded yearly. At the end of ten years how much savings will there be in the savings account?

500*(1.05)^10 = 814.45

this is different from what you specified by the title
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The following information relates to three (3) possible capital expenditure projects. Because of capital rationing only one project can be accepted.

Projects

A                    B                      C

Initial cost                               \$200,000         \$230,000         \$180,000

Expected life                   5 years             5 years             4 years

Scrap value expected                \$10,000           \$15,000             \$8,000

Expected cash inflows                                \$                     \$                       \$

End Year         1                          80,000           100,000             55,000

2                          70,000             70,000             65,000

3                          65,000             50,000             95,000

4                          60,000             50,000           100,000

5                          55,000             50,000                 -

The company estimates its cost of capital is 18% and discount rate factors are:

Year 1             0.8475

Year 2             0.7182

Year 3             0.6086

Year 4             0.5158

Year 5             0.4371

Calculate:

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2. The Accounting Rate of Return (ARR) for each project
3. The Net Present Value (NPV) of each project
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5. Explain the factors management would need to consider – in addition to the financial factors before making a final decision on a project.
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P = \$500

R = 5%

T = 10 years

I = ?? A = ??

Formula: I = PRT/100 = (500*5*10)/100 I = \$250

now, A = P + I = \$500 + \$250 = \$750

the amount in saving account will be \$750
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500=P(Present Value) .05 or 5%=nominal rate(j) 10=period(n) annually=conversion period(m) I=P(1+j/m)^nm I=500*(1+.05)^10 I=814.45
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