subtract the following

3x-8 over 3x subtract 8 over 7y
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[(3x-8) / 3x] -(8/7y) . . . . [(3x-8) / 3x] =(8/7y) . . . (3x-8)=3x*(8/7y) . . . (3x-8)*y=(3*8/7)x . . . or y=(24/7)x/(3x-8) . . . . . .
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