basic algebra word problem

Question

SOLVE IN TERMS OF TWO VARIABLES: 1. One solution containing 20% alcohol is mixed with another solution containing 60% alcohol to make 10 gal of a solution that is 32% alcohol. How much of each solution is used? Let x = number of gal of 1st solution, Let y = number of gal of 2nd solution, _____= amount of alcohol in 1st solution, _____= amount of alcohol in 2nd solution, _____= amount of alcohol if the two solutions are mixed, form the equations: _______________ =______________ and _______________= ______________

Answer 1

20% av x + 60% av y=32% av 10 gallon=3.2 gal . . . x+y =10 or y=10-x . . . 0.2x +0.6y=3.2 . . . 0.2x +0.6*(10-x)=3.2 . . . 0.2x -0.6x +6=3.2 . . . -0.4x=3.2-6=-2.8 . . . x= =2.8/ +0.4 . . . x=7, so y=3