Pentagon Angles, find x help.

The question is: A pentagon has angles x°,(x-20)°,(x-52)°,(x-9)° and (x+12)°. Find x
in Algebra 1 Answers by Level 1 User (120 points)

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1 Answer

angels in pentagon=x+(x-20) +(x-52) +(x-9) +(x+12) . . . =5x-69 deg . . . pentagon=5 sides, so sum av inside angels=3*(180 deg)=540 deg . . . 5x-69=540 . . . 5x=540+69=609 . . . x=609/5=121.8 deg
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