how to solve the rational expression 3x/6x^2-5x

it is asking if their is a restriction
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(3x /6x^2) -5x=0 . . . =(1/2)/x -5x=0 . . . so, 0.5 -5x^2=0 . . . or 1 -10x^2=0 . . . thus, 10x^2=1, or x^2=0.1 . . . x=+-0.316227766
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