if you 43 heads of pigs and chickens and counted 96 feet, how many pigs and chickens do you have?

Question

I'm trying to figure out how to do this math problem. A farmer counted 43 heads of chickens and pigs, and 96 feet. How many chickens and how many pigs are there? Can you show me how to do this problem?

Answer 1

1. x+y=43, or y=43-x . . . 2. 2x +4y=96 . . . 2x +4(43 -x)=96 . . . 2x-4x=96-172 . . . -2x=-76 . . . x=76/2=38...chickens . . . num pigs=43-38=5 . . . feet...4*5 +2*38=20+76=96

Answer 2

How old are you? This problem can be solved so easily using algebra. If u are in high school and don't know how to do this, you're in big trouble.

Let x= number of pigs and y= number of chickens

x+y=43

4x+2y=96

43-y=x

4(43-y)+2y=96

172y-4y+2y=96

172-96=2y(4y-2y)

76=2y

38=y

5=x

Comments

Yeah ur in BIG trouble if u don't know how

---

hey how come u have the same username as me???????????????!!!!!!!! That's not fair. Im teelling