(x^2)=(3x+10)
need help insolving this problem.
(x^2) = (3x + 10)
x^2 = 3x + 10
x^2 - 3x - 10 = 0
(x - 5) (x + 2) = 0
Set each factor to zero and solve for x.
x - 5 = 0 x + 2 = 0
x = 5 x = -2
You can plug those values into the
original equation to check them.
(x^2) = (3x + 10)
(5^2) = (3(5) + 10)
25 = 15 + 10
25 = 25
(x^2) = (3x + 10)
((-2)^2) = (3(-2) + 10)
4 = -6 + 10
4 = 4