y1 = 10 x +6, y2 = 12x - 7 and y1 exceeds y2 by 3 what is the value of x?

I am trying to find the process of solving the above problem , the value of x I'm assuming y1 is y to the first degree an so on for y2, can you help?
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1 Answer

y1=10x+6 . . . y1=12x-7+3 . . . thus, 10x+6=12x-4 . . . 12x-10x=6+4 . . . 2x=10 . . . x=5
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