Wall for Jennifer A. Cascaño

Sep 23, 2018 by iamrussellchii24
hmm good work you have been rated as the top scorer..
Nov 7, 2014 by anonymous
Fine here too..except I'm kinda getting addicted to this website
Jul 10, 2014 by 6482840
Busy but im fine,thanks for asking. How about you 6482840
Jun 26, 2014 by Jennifer A. Cascaño
How are you?
Jun 2, 2014 by 6482840
hi, can you help differentiate sec^3(tan^2 3x)... thanks
Apr 12, 2014 by anonymous
(a)Show that x→∞f(x)=limh→0f(1/h) ,and
 limh→-∞=limh→0- f(1/h)
(b) from (a),deduce that limx→∞xsin(1/x)=1.
Mar 3, 2014 by joebright
help me solve.. Limx→1[( x6 -1)÷(x3-1)]
Feb 28, 2014 by joebright
this is the real work, log base x of 9 + log (base x  squared) of 3= 2.5
Feb 3, 2014 by anonymous
FOR CRACKER:

ANSWER:

log base x of 9 + log base x of 3^2= 2.5 →
log base x of 3^2 + log base x of 3^2=5/2
→ 2 log base x of 3+2 log base x of 3=5/2
→ log base x of 3=5/8 therefore x^5/8 =3
→ x=3^8/5 ,
Or X=5√3^5•3^3=3(5√27)
Feb 2, 2014 by Jennifer A. Cascaño
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