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two years ago my age was four times that of my son eight years ago my age was ten times that of my son.find the age of my son

Let S be the current age of my son.

Let M be the current age of me.

(M - 2) = 4(S - 2)          (two years ago my age was four times that of my son)

(M - 8) = 10(S - 8)        (eight years ago my age was ten times that of my son)

Simplifying the above two equations gives us,

M - 4S = -6

M - 10S = -72

Subtracting 2nd eqn from 1st,

6S = 66

S = 11

M = 4S - 6 = 44 - 6 = 38

Our current ages are: Me 38 yrs, Son 11 yrs

by Level 11 User (81.5k points)

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