I need help with the function f(x)=ax^3+bx^3+cx+d for which f(0)=-2,f(1)=5,f(-1)=3,f(2)=4 I am pretty confused.
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f=(a+b)x3 +cx+d... f(0)=-2, so d=-2... f(1)=5, so a+b+c-2=5, so a+b+c=7. . . . f(-1)=3, so -a-b-c-2=3....a+b+c =-5 ###### problem. . . . f(2)=4...8*(a+b)+2c=4, or 4*(a+b)+c=2 (tri sumthun heer)
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