y"+y'+9y=0 y'(0)=0, y(0)=0.16
Note that ℒ{y"}=s²Y(s)-sy(0)-y'(0) and ℒ{y'}=sY(s)-y(0).
Also, for s>a, ℒ{eᵃᵗsinwt}=w/((s-a)²+w²) and ℒ{eᵃᵗcost}=(s-a)/((s-a)²+w²).
Apply ℒ to both sides:
s²Y-sy(0)-y'(0)+sY-y(0)+9Y=s²Y-0.16s+sY-0.16+9Y=0 from given initial conditions;
Y(s²+s+9)=0.16(s+1);
Y=0.16(s+1)/(s²+s+9).
Y=0.16[((s+½)+½)/((s+½)²+8.75)];
Y=0.16[(s+½)/((s+½)²+8.75)+(√8.75/17.5)(√8.75/((s+½)²+8.75)].
(These steps arrange the expression into a form which lends itself to converting back from Laplace Transform.)
Apply inverse ℒ to both sides:
y(t)=0.16[(e^-(t/2))cos(t√8.75)+(√8.75/17.5)(e-(t/2))sin(t√8.75)].