(9x^3-6x^2+3x-8)/(3x-4)

what is the quotient and the remainder
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1 Answer

Algebraic long division:

          3x2  +2x+11/3 (quotient)

3x-4 ) 9x3   -6x2+3x -8

          9x3-12x2 (subtract)

                   6x2+3x

                   6x2-8x (subtract)

                         11x-8

                         11x-44/3 (subtract)

                                 20/3 remainder

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