The figure has three points in a vertical line because they have the same x coordinate x=-2. Label the points A(-2,2), B(2,2), C(-2,7), D(-2,-2). The area of the plane figure=½CD×AB=½9×4=18 square units, because the base CD=AC+AD=(7-2)+(2-(-2))=5+4=9 units.
This is a plane figure so it cannot have a volume. However, if the figure represents a net (the surfaces of the sides are opened out to lie flat) then the solid figure does have a volume. So the base of this figure is AB with length 2-(-2)=2+2=4. It has four triangular sides: ABC, ABD (base), ACD and BCD, so it's a tetrahedron, in which AC and AD are perpendicular to AB. AB=4, AC=5, AD=4. The volume is (AB.AC.AD)/6=(4×5×4)/6=80/6=40/3 cubic units. V=⅓(base area×height).