Let the solution be y. So, y = e^ln(π)
Apply the natural log to both sides. ln(y) = ln{e^ln(π)}
Here, ln{e^ln(π)} = ln(π)·ln(e) and ln(e) = 1
So, ln(y) = ln{e^ln(π)} = ln(π)·ln(e) = ln(π) Thus, ln(y) = ln(π)
Answer: e^ln(π)** = π (= 3.141592653…)
** in this expression (π) can be replaced by any positive real numbers.
For example, e^ln(AX²) = AX²