Probability p=0.12. Let q=1-p=0.88.
(p+q)¹¹=p¹¹+11p¹⁰q+(11)(10)p⁹q²/2+(11)(10)(9)p⁸q³/6+...
The probability of exactly 8 out of 11 players is therefore:
(11)(10)(9)p⁸q³/6=165(0.12⁸)(0.88³)=0.000004835 (0.00048% approx).
This is 1/206832 approx.
If p=0.121, then q=0.879 and the probability is 0.000005149 (0.00051% approx). This is 1/194208 approx.
So it is highly improbable! It suggests that there is a factor other than randomness operating here. Maybe left-footers make better players!