a) Slope, m = (14-8)/(3-0) = 6/3 = 2
So the equation is y - 8 = 2x or y = 2x +8
b) product of slopes of perpendicular lines is -1
ie. m1 = -1/m2
So the slope of the line is 2.
Therefore the slope of line perpendicular to it is -1/2 or -0.5
therefore the equation of line perpendicular to it is
y = 0.5x + k, where k ∈ R
an instance would be
y = 0.5x + 8