My guess is that you have provided the sample size, sample mean and standard deviation (SD).
Sample size=289, sample mean=43.5, sample SD, s=5.2. Sample variance=s²=5.2²=27.04.
Sample variance=∑(x-43.5)²/(n-1) where n=sample size 289 and x is a datum in the sample dataset, so, if we replace ∑(x-43.5)² by X, then s²=X/288=27.04, making X=7787.52. Population variance σ² is X/n=X/289=7787.52/289=26.9464 approx, compared with 27.04 for the sample. Population SD=σ=√(population variance)=5.19.
So from the given figures, mean=43.5 and population SD is estimated as 5.19. The formula σ=s√((n-1)/n) could have been used, σ=s√(288/289)=(12/17)s√2=0.9983×5.2=5.19 approx.