(1/ 2 , 3/ 2) We check the point by showing that the coordinates satisfy the equation of the unit circle. x^2 + y^2 = 1 /2^ 2 + (?)^ 2 = 1 /4 + (?)/ 4 = (?)Thus, the point 1 /2 , square 3 /2 does lie on the graph of the unit circle.
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

x²+y²=1 is the equation of the unit circle with centre at the origin.

The point (½,√3/2) lies on the circle because ½²+(√3/2)²=¼+¾=1.
by Top Rated User (1.1m points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,447 questions
99,051 answers
2,412 comments
4,787 users