(a) h(x-1) as x➝2, is h(2-1)=h(1)=4/3 and x.h(x-1)=2h(1)=8/3 since the curve is continuous.
(b) h(3+x) as x➝0 is h(3)=1, so the numerator is 0 because h(3+x)=h(3)=1 and 1-1=0. The denominator is non-zero so we are not dividing by zero, and the limit is 0.