Problem: x/2+y/3=1, y= x/4-4. systems of equations
it wud be great if u cud swolve (((((((((((::::::::::
1) x/2 + y/3 = 1
2) y = x/4 - 4
We have been given the value of y in terms of x, so substitute
that value into equation 1.
x/2 + y/3 = 1
x/2 + (x/4 - 4)/3 = 1
6(x/2 + (x/4 - 4)/3) = 1 * 6
3x + 2(x/4 - 4) = 6
3x + x/2 - 8 = 6
3x + x/2 - 8 + 8 = 6 + 8
3x + x/2 = 14
2(3x + x/2) = 14 * 2
6x + x = 28
7x = 28
7x/7 = 28/7
x = 4
Now, we can solve for y.
y = x/4 - 4
y = 4/4 - 4
y = 1 - 4
y = -3
And we check.
x/2 + y/3 = 1
4/2 + (-3)/3 = 1
2 - 1 = 1
1 = 1
Answer: x = 4, y = -3