Calculate inverse matrix M^-1.
Determinant of the matrix is (1*3*2+1*1*0+0*1*3)-(0*3*0+3*1*1+2*1*1)=6-5=1.
Now, exchange rows and columns of the matrix:
[1 1 0]
[1 3 3]
[0 1 2]
Next, we calculate the determinants for each element of the matrix:
[3 2 1]
[2 2 1]
[3 3 2]
Finally, we need to change the signs alternately:
[3 -2 1]
[-2 2 -1]
[3 -3 2]
The matrix determinant was 1 so we multiply the matrix by the inverse of 1 which is scalar 1, so the matrix is unchanged.
This is the inverse matrix, as can be seen by multiplying the original matrix by it to get the identity matrix.