xsq + ax-2=(x-3)sq -b
Solution:
xsq + ax - 2 = ( x - 3 ) sq - b
xsq - 3sq - b = xsq + ax - 2
- 3sq - b = ax - 2
- b = ax - 2 + 3sq
b = 2 - ax - 3sq
Substitute b to the given equation:
xsq + ax - 2 = ( x - 3 ) sq - ( 2 - ax - 3sq )
xsq + ax - 2 = ( x - 3 ) sq - 2 + ax + 3sq
xsq + ax - 2 = xsq - 3sq - 2 + ax + 3sq
0.
Thus, the value of a and b is 0.