How do I find the simplified form of the difference quotient for the function:  f(x) = ax^4
in Calculus Answers by Level 1 User (180 points)

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How do I find the simplified form of the difference quotient for the function:

f(x) = ax^4  this is simple, remember that the a is a constant.  so there is NO PRODUCT.

f'(x) = 4ax^3

by
But the multiple choice that i have to choose from are:
a(h^3 + 4xh^2 + 4x^2h + 4x^3)
a(h^3 +4xh^2 + 6x^2h + 4x^3)
ah^3 + 4xh^2 + 6x^2h + 4x^3
a(h^3 + 4xh + 6x^2h) + 4x^3
But the multiple choice that i have to choose from are:
a(h^3 + 4xh^2 + 4x^2h + 4x^3)
a(h^3 +4xh^2 + 6x^2h + 4x^3)
ah^3 + 4xh^2 + 6x^2h + 4x^3

This is the difference quotient form and i am not sure how to start thas.
a(h^3 + 4xh + 6x^2h) + 4x^3

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