This expression (not an equation) can be written in a similar way to an equation for a circle:
2(x2-10x)+2(y2-6y)+50, then complete the squares:
2(x2-10x+25)+2(y2-6y+9)+50-50-18,
2(x-5)2+2(y-3)2-18.
As it stands the original expression is already standard form.
But if this expression equals zero then 2(x-5)2+2(y-3)2-18=0,
(x-5)2+(y-3)2=9 which is the equation of a circle centre (5,3) and radius 3.
It's likely that the intended meaning of the question is to standardise the equation:
2x2+2y2-20x-12y+50=0 which would be the equation of a circle (see above).