The statement is true. In 3-space there is always a common plane, a plane on which the two lines can be drawn. That plane of reference is the x-y plane then the two lines can be represented by two linear equations: y=ax+b and y=cx+d where a, b, c, d are constants, and a is not equal to c (that is, they are not parallel). Therefore ax+b=cx+d, implies x=(d-b)/(a-c) and y=a(d-b)/(a-c) + b= (ad-ab+ab-bc)/(a-c)=(ad-bc)/(a-c) making the intersection point:
((d-b)/(a-c),(ad-bc)/(a-c)). This represents a point in all cases except when a=c, which is the parallel case.