what is the equation when the slope 8/9, passing through (2,-8)
The equation of a straight line passing through the two points (x1, y1), (x2, y2) is given by
(y - y1) / (x - x1) = (y2 - y1) / (x2 - 1)
where the quotient (y2 - y1) / (x2 - x1) is called the slope, m.
Since we have the slope m = 8,9, then
(y - y1) / (x - x1) = 8/9
Using the point (x1, y1) = (2, - 8)
(y - (-8)) / (x - 2) = 8/9
(y + 8) / (x - 2) = 8/9
y + 8 = (8/9)*(x - 2)
y + 8 = (8/9)x - 16/9
y = (8/9)x -16/9 - 8
y = (8/9)x - 88/9
y = (8/9)x - 9 7/9