If ABC is a triangle then CAB is also a triangle and can't be a straight line. One side and one angle is insufficient to define the triangle. ABC could be scalene, isosceles, right-angled or equilateral. If it's right-angled, and C is the right angle, then AC/AB=1/2 so AB=2AC=2*65=130cm and BC=sqrt(130^2-65^2)=112.58cm. If B is the right angle then BC=56.29cm (half of 112.58cm). If ABC is isosceles it's also equilateral and BC=AC=65cm. If ABC is scalene, then AB and AC can be any length because the other two angles only have to add up to 180-65=115 degrees: BC/sin60=AC/sinB (sine rule), so BC=65sin60/sinB=56.29/sinB where 0<B<115 (angle ABC is between 0 and 115 degrees), and BC would be at least 62.11cm (when ABC is nearly 115 degrees).