When two dice are thrown
the sample space is
S={ 1,1 2,1 3,1 4,1 5,1 6,1
1,2 2,2 3,2 4,2 5,2 6,2
1,3 2,3 3,3 4,3 5,3 6,3
1,4 2,4 3,4 4,4 5,4 6,4
1,5 2,5 3,5 4,5 5,5 6,5
1,6 2,6 3,6 4,6 5,6 6,6 }
n(S)=36
Let A be the event of getting multiple of 2on 1 dice and multiple of 3 on other dice
A={2,3 2,6 4,3 4,6 6,3 6,6}
n(A)=6
P(A)=n(A)/n(S)
=6/36
=1/6
Let B be the event of getting multiple of 3 one one dice and multiple of 2 on other dice
B={3,2 3,4 3,6 6,2 6,4 6,6}
n(B)=6
P(B)=n(B)/n(S)
=6/36
=1/6
The probability of getting multiple of 2 on one dice and multiple of 3 on other dice is 1/6 and the probability of getting multiple of 3 on 1 dice and multiple of 2 on other dice is 1/6