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1 Answer

df/dx=3x²/3x+2xln(3x)=0 at extrema.

So x(1+2ln(3x))=0, so x=0 and ln(3x)=-½, 3x=0.6065 approx, x=0.2022 approx.

Differentiate again: 1+2ln(3x)+2=3+2ln(3x)=3-1>0, so it’s a min.

Answer c.

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