Math Homework Answers - Recent questions and answers in Statistics Answers
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Powered by Question2AnswerAnswered: The mean percent of childhood asthma prevalence in 43 cities is 2.28%. A random sample of 34 of these cities is selected.
https://www.mathhomeworkanswers.org/274835/percent-childhood-asthma-prevalence-sample-cities-selected?show=274860#a274860
<p style="text-align: justify;">The test statistic is (2.6-2.28)/1.28=0.25 corresponding to a probability 0.5987, meaning that 59.87% of the population probably has a mean asthmatic population of less than 2.6%. So 100-59.87=40.13% of asthmatics are more than 2.6% of the overall population. The sample size of 34 is about 79% of the 43 cities constituting the whole population. Since the sample size is so high compared to the population, no adjustment has been made to the standard deviation. I’ve just used the Z score to look up the probability in the Normal Dustribution Table.</p>Statistics Answershttps://www.mathhomeworkanswers.org/274835/percent-childhood-asthma-prevalence-sample-cities-selected?show=274860#a274860Sat, 20 Jun 2020 18:34:12 +0000Answered: (FULL QUESTION BELOW) What is the probability that the mean height for the sample is greater than 65 inches? Assume sigma=2.81.
https://www.mathhomeworkanswers.org/274831/question-probability-height-sample-greater-inches-assume?show=274834#a274834
<p style="text-align: justify;">The test statistic is (65-64.3)/(2.81)=0.2491. This corresponds to 0.5984, implying 59.84% of the heights are less than 65 inches, so 1-0.5984=0.4016 or 40.2% heights are greater than 65 inches.</p>
<p style="text-align: justify;"> </p>Statistics Answershttps://www.mathhomeworkanswers.org/274831/question-probability-height-sample-greater-inches-assume?show=274834#a274834Fri, 19 Jun 2020 23:53:48 +0000Answered: At least 75% of the observations lie between which two values?
https://www.mathhomeworkanswers.org/274776/at-least-75-of-the-observations-lie-between-which-two-values?show=274777#a274777
<p>Given, µ = 22 and σ =3</p>
<p>From <span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">Chebyshev's Theorem,</span></p>
<p><span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">1 - 1/k^2 = .75 => k = 2</span></p>
<p><span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">Since observation lies between ( </span>µ<span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">-k</span>σ, µ+kσ) because they are symmetric around the mean.</p>
<p>i.e, (22-2*3, 22+2*3) => (16,28)</p>
<p>So the values are 16 and 28</p>
<p><br>
</p>Statistics Answershttps://www.mathhomeworkanswers.org/274776/at-least-75-of-the-observations-lie-between-which-two-values?show=274777#a274777Wed, 17 Jun 2020 21:02:11 +0000Answered: I've got this Connections to Discrete Random Variables homework to do but I'm tired!
https://www.mathhomeworkanswers.org/274603/this-connections-discrete-random-variables-homework-tired?show=274716#a274716
<p style="text-align:justify"><span style="font-size:14px">TASK A</span></p>
<p style="text-align:justify"><span style="font-size:14px">1. Kristen has 150 red tiles, 250 blue tiles and 350 green tiles. She grabs a big handful of 50 tiles all at once and places them on a table where she counts to see how many of them are green.</span></p>
<p style="text-align:justify"><span style="font-size:14px">a. Hypergeometric or Binomial: Hypergeometric</span></p>
<p style="text-align:justify"><span style="font-size:14px">b. What is the probability that she pulled out exactly 21 green tiles? 0.092961</span></p>
<p style="text-align:justify"><span style="font-size:14px">c. What is the probability that she pulled out at least 21 green tiles? 0.796748</span></p>
<p style="text-align:justify"><span style="font-size:14px">2. Kawhi Leonard’s career field goal percentage is 0.475. In each round of the playoffs, he is expected to shoot around 160 shots. I am wondering how many of those shots will be successful.</span></p>
<p style="text-align:justify"><span style="font-size:14px">a. Hypergeometric or Binomial: Binomial</span></p>
<p style="text-align:justify"><span style="font-size:14px">b. What is the probability that he hits exactly 80 of those shots? 0.051551</span></p>
<p style="text-align:justify"><span style="font-size:14px">c. What is the probability that he hits less than 70 of those shots? 0.151708</span></p>
<p style="text-align:justify"><span style="font-size:14px">3. Caleb is conducting a survey in his old elementary school. The school has 650 students in total and he knows that exactly 14% of the students in the school are in grade 8. He decides to randomly survey 55 students in the school and is interested in knowing how many of them are in grade 8.</span></p>
<p style="text-align:justify"><span style="font-size:14px">a. Hypergeometric or Binomial: Hypergeometric</span></p>
<p style="text-align:justify"><span style="font-size:14px">b. What is the probability that exactly 9 of the students are in grade 8? 0.132527</span></p>
<p style="text-align:justify"><span style="font-size:14px">c. What is the probability that more than 11 of the students are in grade 8? 0.066731</span></p>
<p style="text-align:justify"><span style="font-size:14px">TASK B/C not defined?</span></p>
<p style="text-align:justify"><span style="font-size:14px">NORMAL APPROXIMATION</span></p>
<p style="text-align:justify"><span style="font-size:14px">Before applying this approximation, we need to ensure that our sample is less than one tenth of the population, otherwise the approximation will not be sufficiently accurate:</span></p>
<p style="text-align:justify"><span style="font-size:14px">(1) 50/750=1/15 OK.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(2) The goal average 0.475 is taken over a whole career, consisting of many rounds, so we can assume that 1 round is a small percentage of that career.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(3) 55/650<1/10 OK.</span></p>
<p style="text-align:justify"><span style="font-size:14px">Now need the mean and standard deviation:</span></p>
<p style="text-align:justify"><span style="font-size:14px">(1) Mean=50×350/750=70/3 (23.33...), applying the same proportion to the sample (50 tiles) as is found in the population (350 green tiles divided by total tiles). For SD we need the failure fraction = (750-350)/750=1-350/750=8/15 (0.533...). We also need (N-n)/(N-1)=where N=750, n=50=100/107 (0.9345...)</span></p>
<p style="text-align:justify"><span style="font-size:14px">SD=√((70/3)(8/15)(100/107))=3.41 approx.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(1b) To estimate the probability for a discrete value we need to apply a correction: 9 is equivalent to the range 20.5-21.5. We need Z scores for each (Z₁ and Z₂): Z₁=(20.5-(70/3))/3.41=-0.83 approx; Z₂=(21.5-(70/3))/3.41=-0.54 approx. Percentages are 0.203 (Z₁) and 0.295 (Z₂), the difference is 0.092, which compares favourably with the former figure of 0.093.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(1c) “At least 21” means the minimum is 20.5 after correction, so Z=-0.83 corresponding to a probability of 0.203 (for X≤21) therefore, for X≥21 we use 1-0.203=0.797, same as (1c) in Task A, after rounding.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(2) Mean=0.475×160=76; SD for Binomial is √(160(0.475)(1-0.475))=√((76)(0.525))=6.32 approx.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(2b) Range correction on 80 is 79.5-80.5. Z₁=(79.5-76)/6.32=0.554, Z₂=(80.5-76)/6.32=0.712, corresponding to 0.710 and 0.762. Therefore 0.762-0.710=0.052, same as (2b) in Task A, after rounding.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(2c) Correction for <70 is <69.5, Z=(69.5-76)/6.32=-1.029 corresponding to 0.152, same as (2c) in Task A, after rounding.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(3) Probability of Grade 8 students=0.14, corresponding to 0.14×650=91 students. Mean=0.14×55=7.7 for the sample of 55 students. SD=√((7.7)(0.86)(650-55)/649)=2.46. Range correction for 9 is 8.5-9.5.</span></p>
<p style="text-align:justify"><span style="font-size:14px">Z₁=(8.5-7.7)/2.46=0.325, corresponding to 0.627; Z₂=(9.5-7.7)/2.46=0.731, corresponding to 0.767, so the approximation is 0.767-0.627=0.140 compared to 0.133 in Task A.</span></p>
<p style="text-align:justify"><span style="font-size:14px">“More than 11” after correction is ≥11.5. Z=(11.5-7.7)/2.46=1.54, corresponding to 0.938. But this is ≤11.5, so for ≥11.5, we need 1-0.938=0.062, compared to 0.067 in Task A.</span></p>Statistics Answershttps://www.mathhomeworkanswers.org/274603/this-connections-discrete-random-variables-homework-tired?show=274716#a274716Mon, 15 Jun 2020 22:07:53 +0000Answered: If a pair of dressers differ by 30 years in year of construction, by how much would we predict their prices at auction to differ (round to nearest dollar)?
https://www.mathhomeworkanswers.org/274588/dressers-differ-construction-predict-auction-nearest-dollar?show=274599#a274599
Data insufficient to deduce anything.<br />
<br />
Requires initial price, the rate by which the price falls per year, bidders mood etc.Statistics Answershttps://www.mathhomeworkanswers.org/274588/dressers-differ-construction-predict-auction-nearest-dollar?show=274599#a274599Fri, 12 Jun 2020 08:41:35 +0000Answered: Describe a real-life set of data that could be described by: X~N(68000, 9000^2). Include units.
https://www.mathhomeworkanswers.org/274343/describe-life-data-that-could-described-68000-include-units?show=274354#a274354
<p style="text-align: justify;">$68,000 could be an average annual salary with a standard deviation of $9000 (13% of the mean). This would give an expected salary range of $59,000-$77,000. The normal distribution would show the probability of selecting a randomly selected salary X.</p>
<p style="text-align: justify;">The second example has a standard deviation of 12 (about 5% of the mean) indicating a narrow spread 218-242. This could be the number of miles a car starting with a full tank of fuel could be driven before needing refuelling. The normal distribution would show how likely refuelling would be necessary for a journey of X miles.</p>Statistics Answershttps://www.mathhomeworkanswers.org/274343/describe-life-data-that-could-described-68000-include-units?show=274354#a274354Thu, 04 Jun 2020 16:22:50 +0000Answered: If the researcher decides to test this hypothesis at the 0.05 level of significance, determine the critical value.
https://www.mathhomeworkanswers.org/274334/researcher-decides-hypothesis-significance-determine-critical?show=274349#a274349
<p style="text-align: justify;">This question seems to be related to:</p>
<p style="text-align: justify;"><a rel="nofollow" href="https://www.mathhomeworkanswers.org/274332/if-x-bar-57-2-and-s-9-6-compute-the-test-statistic?show=274348#a274348">https://www.mathhomeworkanswers.org/274332/if-x-bar-57-2-and-s-9-6-compute-the-test-statistic?show=274348#a274348</a></p>Statistics Answershttps://www.mathhomeworkanswers.org/274334/researcher-decides-hypothesis-significance-determine-critical?show=274349#a274349Thu, 04 Jun 2020 11:06:55 +0000Answered: if x-bar = 57.2 and s = 9.6, compute the test statistic
https://www.mathhomeworkanswers.org/274332/if-x-bar-57-2-and-s-9-6-compute-the-test-statistic?show=274348#a274348
<p style="text-align:justify">The t-test statistic t=(60-57.2)/(9.6/√20)=1.30 approx. (The sample standard deviation has to be adjusted to 9.6/√n where n is the sample size.) When using the t-tables the number of degrees of freedom = n-1 = 19 in this case. Since we are only considering mean < 60, it is a one-tail test. (A 2-tail test would apply if we were considering mean ≠ 60, that is, mean <> 60.) Then the significance level or confidence level needs to be known to decide whether to accept or reject H₀. If the significance level is 0.05 (95% confidence level), tables give a critical value of 1.79, compared to the calculated 1.30 test value. So it would appear that we do not reject H₀.</p>Statistics Answershttps://www.mathhomeworkanswers.org/274332/if-x-bar-57-2-and-s-9-6-compute-the-test-statistic?show=274348#a274348Thu, 04 Jun 2020 10:45:03 +0000Answered: In a recent survey, 58% of voters indicated that they voted for the incumbent mayor. This survey is considered accurate within plus or minus 4%, 19 times out of 20.
https://www.mathhomeworkanswers.org/274320/recent-survey-indicated-incumbent-survey-considered-accurate?show=274326#a274326
<p style="text-align:justify">The range of percentages is 58-4=54% to 58+4=62%. If there were N voters, then 0.62N-0.54N= 0.08N constitutes 19/20=95% of the voters for the incumbent mayor. For example, if there were 95,000 voters, then between 51,300 and 58,900 voters (7600 voters) voted for the incumbent mayor. So 7,600 voters would represent 95% of those voting for the incumbent mayor, making the total number of such voters 100×7600÷95=8,000 voters. The likelihood is that 400 voters who voted for the incumbent mayor have been excluded from the count. Answer b seems to fit the situation.</p>Statistics Answershttps://www.mathhomeworkanswers.org/274320/recent-survey-indicated-incumbent-survey-considered-accurate?show=274326#a274326Wed, 03 Jun 2020 18:07:04 +0000Answered: What is the quantity of 20 objects when an odd number is added to 5 parts?
https://www.mathhomeworkanswers.org/273546/what-is-the-quantity-of-20-objects-when-odd-number-added-parts?show=274264#a274264
<p style="text-align:justify">All odd numbers can be represented by 2n+1 where n≥0 is an integer.</p>
<p style="text-align:justify">One part is 20/5=4 units. Now add the odd number to 4: 4+2n+1=2n+5, assuming that the odd number is added to each of the 5 parts.</p>
<p style="text-align:justify">The new part is 2n+5, so 5 of them make 5(2n+5)=10n+25. This is the quantity that 20 becomes. When n=0, 20 becomes 25 and when n=1, 20 becomes 35, and so on.</p>Statistics Answershttps://www.mathhomeworkanswers.org/273546/what-is-the-quantity-of-20-objects-when-odd-number-added-parts?show=274264#a274264Tue, 02 Jun 2020 10:01:51 +0000Answered: How to find the vale of mean of of unknown group of data with median, mode and range given?
https://www.mathhomeworkanswers.org/273741/find-vale-mean-unknown-group-data-with-median-mode-range-given?show=273757#a273757
<p style="text-align: justify;">(a+b+c+d)/4 is the mean, where d≥c≥b≥a. The median is (b+c)/2=2.5; the range d-a=2. So b+c=5, therefore (a+5+d)/4 is the mean. And d=a+2, so (a+5+a+2)/4=(2a+7)/4 is the mean. The value 3 is repeated. Since the median is 2.5, b and c can’t both be 3. If c=d=3, then b=5-c=2; if a=b=3, then c=2. Since c must be greater than b by definition, then the former must be true: (a,b,c,d)=(a,2,3,3). Therefore a=3-2=1, so the dataset is 1,2,3,3 and the mean is 9/4=2.25.</p>Statistics Answershttps://www.mathhomeworkanswers.org/273741/find-vale-mean-unknown-group-data-with-median-mode-range-given?show=273757#a273757Sat, 16 May 2020 10:56:41 +0000Answered: Describe the key difference between the binomial distribution and the hypergeometric distribution.
https://www.mathhomeworkanswers.org/273656/describe-difference-distribution-hypergeometric-distribution?show=273691#a273691
<p style="text-align: justify;">Answer a. Independence means that the probability of an event (for example, head or tail in a coin flip) does not affect subsequent coin flips and is not affected by previous coin flips. The number of trials is unlimited.</p>
<p style="text-align: justify;">Dependence means that the probability of an event affects the probability of a subsequent event. For example, drawing a particular suit from a pack of cards without replacing it into the pack changes the probability of drawing the next card, because there will be one fewer card and one less suit remaining.</p>Statistics Answershttps://www.mathhomeworkanswers.org/273656/describe-difference-distribution-hypergeometric-distribution?show=273691#a273691Thu, 14 May 2020 12:07:12 +0000Answered: Five cards are dealt from a standard deck. What is the expected number of hearts?
https://www.mathhomeworkanswers.org/273655/five-cards-dealt-from-standard-deck-expected-number-hearts?show=273678#a273678
<p style="text-align: justify;">In a pack of 52 cards we can expect to find 13 hearts; so by simple proportion in a group of 5 cards we can expect to find 5/52×13=5/4=1.25 hearts, answer d.</p>Statistics Answershttps://www.mathhomeworkanswers.org/273655/five-cards-dealt-from-standard-deck-expected-number-hearts?show=273678#a273678Thu, 14 May 2020 06:09:17 +0000Answered: True or false. P(n, r) = r! C(n, r).
https://www.mathhomeworkanswers.org/77051/true-or-false-p-n-r-r-c-n-r?show=273432#a273432
<p style="text-align: justify;">In answer to the title question, the statement is true.</p>Statistics Answershttps://www.mathhomeworkanswers.org/77051/true-or-false-p-n-r-r-c-n-r?show=273432#a273432Wed, 06 May 2020 21:02:40 +0000Answered: A club with 20 women and 15 men need to form a committe of size 7. How many committees are possible?
https://www.mathhomeworkanswers.org/273368/club-with-women-form-committe-size-many-committees-possible?show=273376#a273376
<p style="text-align:justify">Assuming that all members of the committee have equal status, then this question amounts to finding out how many combinations of 7 from 35 people (men and women) there are.</p>
<p style="text-align:justify">To start building the committee we take one of the people, so we have a choice of 35. For the next member of the committee we have 34 people to choose from, and so on. So we have 35×34×33×32×31×30×29 ways. But we picked them in order. The person we chose first could have been the last to be picked, we would still end up with the same combination of people. So we need to divide by the number of ways we can arrange 7 people=7×6×...×1=5040 or 7!. When we do this division we get 6,724,520 as the total number of ways of choosing 7 people from 35.</p>
<p style="text-align:justify">Note that these ombinations include a committee of all women and a committee of all men. The answer would be different if a certain number of men or women had to be in the committee.</p>Statistics Answershttps://www.mathhomeworkanswers.org/273368/club-with-women-form-committe-size-many-committees-possible?show=273376#a273376Tue, 05 May 2020 20:08:19 +0000Answered: What's the probability of the next 30, 40, 50 people sampled?
https://www.mathhomeworkanswers.org/272955/whats-the-probability-of-the-next-30-40-50-people-sampled?show=273068#a273068
<p style="text-align:justify">(1) The probability of exactly 25/40 being pro-choice on abortion, if subjected to binomial distribution, that is, (p+q)ⁿ where n=40, p=0.57 and q=1-p=0.43, is given by ⁴⁰C₂₅p²⁵q¹⁵=0.10 or 10% approximately. In other words all arrangements of 40 people such that 25 are pro-choice and 15 are con-choice on abortion.</p>
<p style="text-align:justify">(2) We need the cumulative probability this time for n=30, so this means summing the relevant terms of the binomial expansion corresponding to (0 pro, 30 con), (1 pro, 29 con), (2 pro, 28 con), ... (15 pro, 15 con). The summation will be q³⁰+30q²⁹p+(30×29/2)q²⁸p²+...+³⁰C₁₆q¹⁶p¹⁴+³⁰C₁₅q¹⁵p¹⁵. By symmetry, ³⁰C₁₆=³⁰C₁₄, etc. The sum comes to 0.276 or about 27.6%. The result can also be obtained from binomial distribution tables, or by using a binomial distribution calculator (also available online).</p>
<p style="text-align:justify">(3) For this we subtract p(x<20) from p(x≤30) (cumulative binomial probabilities) where n=50.</p>
<p style="text-align:justify">p(x≤30)=0.71433 and p(x<20)=0.00527, so p(20≤x≤30)=0.7091 or 70.91% approx.</p>
<p style="text-align:justify">Another way of solving this is to sum the terms from ⁵⁰C₂₀p²⁰q³⁰ to ⁵⁰C₃₀p³⁰q²⁰.</p>Statistics Answershttps://www.mathhomeworkanswers.org/272955/whats-the-probability-of-the-next-30-40-50-people-sampled?show=273068#a273068Mon, 27 Apr 2020 16:04:59 +0000Answered: If the dispense rate is approximately normal was their decision reasonable?
https://www.mathhomeworkanswers.org/272953/dispense-approximately-normal-their-decision-reasonable?show=273051#a273051
<p style="text-align: justify;">The small sample of 16 suggests a t-test with 15 degrees of freedom for a 95% confidence interval (2-tailed). From tables, the t value is about 2.13. The pop SD needs to be reduced because of the sample size to 20/√16=20/4=5, and we need to find X where 2.13=(X-485)/5, so X-485=10.65ml. This I interpret to mean that for 95% confidence, if the dispenser outputs more than 10.65ml away from the mean then their decision is unreasonable. 15ml is greater than this, so their decision is unreasonable.</p>Statistics Answershttps://www.mathhomeworkanswers.org/272953/dispense-approximately-normal-their-decision-reasonable?show=273051#a273051Mon, 27 Apr 2020 13:20:56 +0000Answered: find the solution to the associated linear programming problem
https://www.mathhomeworkanswers.org/48976/find-the-solution-the-associated-linear-programming-problem?show=272719#a272719
<p style="text-align: justify;">Where is the objective function?</p>Statistics Answershttps://www.mathhomeworkanswers.org/48976/find-the-solution-the-associated-linear-programming-problem?show=272719#a272719Tue, 21 Apr 2020 09:34:07 +0000Answered: Question 4 in the document: Which of the following could be the median?
https://www.mathhomeworkanswers.org/272452/question-the-document-which-the-following-could-the-median?show=272476#a272476
<p style="text-align:justify">I think option answer b, but let’s take a closer look at the dataset. There is a total of 52 data, so the median is between the 26th and 27th datum.</p>
<p style="text-align:justify">There are 7 data between 5 and 10, 8 between 10 and 15, 9 between 15 and 20, and 7 between 20 and 25. The 26th and 27th elements are in the range 20 to 25, so 24 is in this range, which is option b.</p>Statistics Answershttps://www.mathhomeworkanswers.org/272452/question-the-document-which-the-following-could-the-median?show=272476#a272476Mon, 13 Apr 2020 14:02:18 +0000Answered: The mean salary of all female workers is $35,000. The mean salary of all male workers is $41,000. What must be true about the mean salary of all workers?
https://www.mathhomeworkanswers.org/272464/salary-female-workers-salary-workers-about-salary-workers?show=272467#a272467
Answer c.Statistics Answershttps://www.mathhomeworkanswers.org/272464/salary-female-workers-salary-workers-about-salary-workers?show=272467#a272467Mon, 13 Apr 2020 10:52:25 +0000Answered: Choose numbers with smallest and largest possible standard deviation. Is more than one choice possible in A and B?
https://www.mathhomeworkanswers.org/272395/numbers-smallest-largest-possible-standard-deviation-possible?show=272406#a272406
<p style="text-align:justify">(a) The smallest SD is 0, when all the numbers are the same (since repeats are allowed). There is no deviation from the mean.</p>
<p style="text-align:justify">(b) The largest SD is when the numbers are 0, 0, 10, 10. The mean is 5 and the variance is 4×25/4=25. The SD is 5.</p>
<p style="text-align:justify">(c) There are 11 possible datasets for (a), since there are 11 whole numbers between 0 and 10. For (b) there is only one dataset.</p>Statistics Answershttps://www.mathhomeworkanswers.org/272395/numbers-smallest-largest-possible-standard-deviation-possible?show=272406#a272406Sun, 12 Apr 2020 10:33:03 +0000Answered: How do I interpret stem plots that are truncated or rounded like this one?
https://www.mathhomeworkanswers.org/272134/how-interpret-stem-plots-that-are-truncated-rounded-like-this?show=272136#a272136
<p style="text-align:justify">(a) The stem is the tens unit for the plot, so 03 or $3 is the lowest amount. Because of rounding, this could be $2.50.</p>
<p style="text-align:justify">(b) The right tail is longer than the left tail of the plot so it’s a distribution with positive skew. The mean is greater than the median. That is, many more shoppers spend comparatively less than those that spend a lot.</p>Statistics Answershttps://www.mathhomeworkanswers.org/272134/how-interpret-stem-plots-that-are-truncated-rounded-like-this?show=272136#a272136Sun, 05 Apr 2020 12:34:44 +0000a. +/- 3
https://www.mathhomeworkanswers.org/272054/a-3
which of the following is accepted value for skewness? +/- 3, +/- 2, +/- 4, +/- 2Statistics Answershttps://www.mathhomeworkanswers.org/272054/a-3Thu, 02 Apr 2020 12:28:30 +0000Answered: Use the table of z-scores to find the percentage of data items in a normal distribution that lie in the given range.
https://www.mathhomeworkanswers.org/271757/table-scores-percentage-items-normal-distribution-given-range?show=271772#a271772
<p style="text-align: justify;">(a) Z=-0.9 corresponds to 18.41% and below. So above this is 81.59%.</p>
<p style="text-align: justify;">(b) 18.41%.</p>
<p style="text-align: justify;">(c) Z=0.4 is 65.54% and below, Z=1.4 is 91.92% and below, within the range is 26.38%.</p>
<p style="text-align: justify;">(d) Z=-1.86 is 3.14% and below, so 96.86% above.</p>
<p style="text-align: justify;">(e) Z=1.94 is 97.38% and below, Z=2.87 is 99.79% and below, so within the range is 2.41%.</p>Statistics Answershttps://www.mathhomeworkanswers.org/271757/table-scores-percentage-items-normal-distribution-given-range?show=271772#a271772Mon, 30 Mar 2020 19:45:40 +0000Answered: normal distribution, with µ = 3.2 and σ = 0.75. (a) What is the maximum score that can be in the bottom 10% of scores? (b) Between what two values does the middle 76% of the scores lie?
https://www.mathhomeworkanswers.org/271538/normal-distribution-maximum-bottom-scores-between-values?show=271665#a271665
<p style="text-align:justify">(a) Z=(X-µ)/σ, so we need the value of Z corresponding to the lower 10%. -1.282 gives us about 0.1.</p>
<p style="text-align:justify">-1.282=(X-3.2)/0.75, so X=3.2-0.75(1.282)=2.24 approx.</p>
<p style="text-align:justify">(b) The middle 76% leaves 24% to be shared equally between the tails of the distribution. So we need the Z value for 2-tail 12%. Z=-1.175 gives the lower 12% so Z=1.175 gives 88% (top 12%). From these two values we can work out the X values. X₁=3.2-0.75(1.175)=2.32, X₂=3.2+0.75(1.175)=4.08. These two values enclose 76% of the scores.</p>Statistics Answershttps://www.mathhomeworkanswers.org/271538/normal-distribution-maximum-bottom-scores-between-values?show=271665#a271665Mon, 30 Mar 2020 13:42:53 +0000Answered: what is the y-intercept of the line as an ordered pair p=97-1.45
https://www.mathhomeworkanswers.org/271011/what-is-the-y-intercept-of-the-line-as-an-ordered-pair-p-97-1-45?show=271024#a271024
<p style="text-align: justify;">The y intercept is 97. This means that for a driver with no experience the premium is 97 currency units. Each successive year of experience reduces the premium by 1.45 currency units.</p>Statistics Answershttps://www.mathhomeworkanswers.org/271011/what-is-the-y-intercept-of-the-line-as-an-ordered-pair-p-97-1-45?show=271024#a271024Wed, 25 Mar 2020 09:20:06 +0000Answered: The mean annual per personconsumption of butter was 5.5 pounds, by 12.2% from 2010. What was the mean annual per person consumption of butter in 2010?
https://www.mathhomeworkanswers.org/270652/annual-personconsumption-butter-person-consumption-butter?show=270656#a270656
<p style="text-align: justify;">If c=2010 consumption, the consumption for the comparison year is 100+12.2 per cent of c=1.122c=5.5.</p>
<p style="text-align: justify;">So 2010 consumption is 5.5/1.122=4.9 lb approx</p>Statistics Answershttps://www.mathhomeworkanswers.org/270652/annual-personconsumption-butter-person-consumption-butter?show=270656#a270656Fri, 13 Mar 2020 08:22:37 +0000Answered: is f(x) = 2(x + 5)3 + 1 is one to one. Is it also onto?
https://www.mathhomeworkanswers.org/40800/is-f-x-2-x-5-3-1-is-one-to-one-is-it-also-onto?show=270196#a270196
<p style="text-align: justify;">Let y=f(x)=2(x+5)3+1=6x+31, therefore x=⅙(y-31). All values of y have a corresponding x value (linear relationship) so f(x) is 1-1 because x is associated with a unique value of y (and vice versa), and f(x) is onto because there is no value of y which has no corresponding x.</p>Statistics Answershttps://www.mathhomeworkanswers.org/40800/is-f-x-2-x-5-3-1-is-one-to-one-is-it-also-onto?show=270196#a270196Sun, 23 Feb 2020 17:29:19 +0000Answered: IF A COMPANY TOOK 300 HOURS TO ASSEMBLE THEIR FIRST UNIT AND 200 HOURS TO ASSEMBLE THE SECOND UNIT, WE MIGHT EXPECT IT TO TAKE
https://www.mathhomeworkanswers.org/262998/company-hours-assemble-their-assemble-second-might-expect?show=269985#a269985
133 4th unitStatistics Answershttps://www.mathhomeworkanswers.org/262998/company-hours-assemble-their-assemble-second-might-expect?show=269985#a269985Fri, 14 Feb 2020 19:44:55 +0000Answered: (10x1/9)+(8.5x2/9)+(7x1/9)+(6x2/9)+(4.5x2/9)+(2x1/9)=
https://www.mathhomeworkanswers.org/29961/10x1-9-8-5x2-9-7x1-9-6x2-9-4-5x2-9-2x1-9?show=269848#a269848
<p style="text-align: justify;">Simplify:</p>
<p style="text-align: justify;">(10+17+7+12+9+2)/9=57/9=19/3=6⅓.</p>
<p style="text-align: justify;"> </p>Statistics Answershttps://www.mathhomeworkanswers.org/29961/10x1-9-8-5x2-9-7x1-9-6x2-9-4-5x2-9-2x1-9?show=269848#a269848Thu, 06 Feb 2020 13:21:10 +0000Answered: how do you graph an equation when one point is at the center and the other point is in the graph?
https://www.mathhomeworkanswers.org/72903/graph-equation-when-point-center-and-the-other-point-the-graph?show=269485#a269485
<p style="text-align: justify;">I assume that by the centre you mean the origin (0,0) and this point is also on the graph. So we have two points (-7,-7) and (0,0). A straight line can be drawn to pass through these points and it has a slope (0-(-7))/(0-(-7))=7/7=1.</p>
<p style="text-align: justify;">This gives us the equation y=1x+a where a is a constant. But the line passes through (0,0) so when x=0, y=0, which means that a=0 and we can remove the 1 so the equation is y=x.</p>Statistics Answershttps://www.mathhomeworkanswers.org/72903/graph-equation-when-point-center-and-the-other-point-the-graph?show=269485#a269485Tue, 14 Jan 2020 13:13:14 +0000Answered: Statistics
https://www.mathhomeworkanswers.org/245867/statistics?show=269325#a269325
<p style="text-align:justify">7a.</p>
<table border="1" cellpadding="1" style="border-spacing:1px; width:500px">
<tbody>
<tr>
<td> </td>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td>Y odd</td>
<td>Y</td>
<td>Y odd</td>
<td>Y</td>
<td>Y odd</td>
<td>Y</td>
</tr>
<tr>
<td>2</td>
<td>Y odd</td>
<td>Y</td>
<td>Y odd</td>
<td>Y</td>
<td>Y odd</td>
<td>N</td>
</tr>
<tr>
<td>3</td>
<td>Y odd</td>
<td>Y</td>
<td>N odd</td>
<td>N</td>
<td>N odd</td>
<td>N</td>
</tr>
<tr>
<td>4</td>
<td>Y odd</td>
<td>Y</td>
<td>N odd</td>
<td>N</td>
<td>N odd</td>
<td>N</td>
</tr>
<tr>
<td>5</td>
<td>Y odd</td>
<td>Y</td>
<td>N odd</td>
<td>N</td>
<td>N odd</td>
<td>N</td>
</tr>
<tr>
<td>6</td>
<td>Y odd</td>
<td>N</td>
<td>N odd</td>
<td>N</td>
<td>N odd</td>
<td>N</td>
</tr>
</tbody>
</table>
<p style="text-align:justify">The above table shows all 36 double roll outcomes. Cells marked with Y are combinations corresponding to ice cream prices of 25c or lower, according to the given rule. There are 18 Y’s out of 36 possible outcomes, so the probability is 18/36=1/2.</p>
<p style="text-align:justify">7b.</p>
<p style="text-align:justify">Assuming that we are looking for affordable prices that are also odd, we need to count the cells containing Y odd. There are 10 cells, so the probability is 10/36=5/18.</p>
<p style="text-align:justify"> </p>
<p style="text-align:justify">You need to submit these questions individually. There are constraints on this website limiting the size of answers.</p>Statistics Answershttps://www.mathhomeworkanswers.org/245867/statistics?show=269325#a269325Sat, 04 Jan 2020 09:31:37 +0000Answered: STATISTICS HOMEWORK....2 QUESTIONS
https://www.mathhomeworkanswers.org/266943/statistics-homework-2-questions?show=269323#a269323
<p style="text-align:justify"><span style="font-size:14px">Z₁=(8.4717-7.42)/2.58=0.4076, Z₂=(9.0778-7.42)/2.58=0.6426.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(A) p(Z₁)=0.6582, p(Z₂)=0.7397, so the probability for the defined range is the difference between these probabilities: 0.0815 approx. This applies to one individual.</span></p>
<p style="text-align:justify"><span style="font-size:14px">(B) In the sample group of 8, the number of degrees of freedom is 7. The SD needs to be adjusted for the sample: 2.58/√8=0.9122 and we use the t test.</span></p>
<p style="text-align:justify"><span style="font-size:14px">t₁=(8.4717-7.42)/0.9122=1.1530, t₂=(9.0778-7.42)/0.9122=1.8174.</span></p>
<p style="text-align:justify"><span style="font-size:14px">From t tables with dof=7, p(t₁)=0.1443, p(t₂)=0.0419, and the difference is 0.1024 approx. This is slightly higher than the probability for one individual.</span></p>Statistics Answershttps://www.mathhomeworkanswers.org/266943/statistics-homework-2-questions?show=269323#a269323Sat, 04 Jan 2020 09:18:51 +0000Answered: Kevin has a total of 17 17 coins consisting of nickels and quarters. The total value of the coins is $2.05 $2.05 . How many of each type of coin does he have?
https://www.mathhomeworkanswers.org/268735/kevin-total-coins-consisting-nickels-quarters-total-coins?show=268737#a268737
<p style="text-align: justify;">n=number of nickels, q=number of quarters.</p>
<p style="text-align: justify;">n+q=17, n=17-q,</p>
<p style="text-align: justify;">0.05n+0.25q=2.05,</p>
<p style="text-align: justify;">0.05(17-q)+0.25q=2.05,</p>
<p style="text-align: justify;">0.85-0.05q+0.25q=2.05,</p>
<p style="text-align: justify;">0.20q=2.05-0.85=1.20,</p>
<p style="text-align: justify;">q=1.20/0.20=6, so n=17-6=11.</p>
<p style="text-align: justify;">11 nickels=$0.55, 6 quarters=$1.50, total $2.05.</p>
<p style="text-align: justify;"> </p>
<p style="text-align: justify;"> </p>Statistics Answershttps://www.mathhomeworkanswers.org/268735/kevin-total-coins-consisting-nickels-quarters-total-coins?show=268737#a268737Sat, 30 Nov 2019 20:56:31 +0000Answered: How many nickels, dimes, and quarters are in the piggy bank?
https://www.mathhomeworkanswers.org/249627/how-many-nickels-dimes-and-quarters-are-in-the-piggy-bank?show=268537#a268537
2 nickels 6 dimes 15 quartersStatistics Answershttps://www.mathhomeworkanswers.org/249627/how-many-nickels-dimes-and-quarters-are-in-the-piggy-bank?show=268537#a268537Thu, 21 Nov 2019 22:36:29 +0000Answered: Estimate Mean Annual Income Of $52,000 Of 16 Agents In The City With Mean Annual Income Of $52,000
https://www.mathhomeworkanswers.org/67814/estimate-annual-income-agents-city-with-mean-annual-income?show=268422#a268422
<p style="text-align:justify">For a large sample size we would use the Z score (2.326) corresponding to a two-tail probability of 98%. This would give us an interval corresponding to 98% of all annual incomes of real estate agents (realtors). It would tell us where we would expect 98% of the annual incomes to be in the whole population of these agents’ annual incomes.</p>
<p style="text-align:justify">But the sample size is small and the number of degrees of freedom (dof) is 16-1=15, so we use the t-distribution for this dof to find out for this sample what the spread would be expected to be. The t value for 98% (2-tail) is 2.602. The extreme limits for this confidence interval is given by (X-52000)/7500=2.602, from which X-52000=19515, giving us the extremes $32485 and $71515, the interval [$32485,$71515], $52000±$19515, or $32,485<X<$71,515, where X represents the annual income.</p>
<p style="text-align:justify">(This compares to the same interval in the whole population of such annual incomes of $34,555<X<$69,445.)</p>Statistics Answershttps://www.mathhomeworkanswers.org/67814/estimate-annual-income-agents-city-with-mean-annual-income?show=268422#a268422Sun, 17 Nov 2019 15:10:53 +0000Answered: Average Math SAT score and an overachieving high school- Statistics, std, Dev help
https://www.mathhomeworkanswers.org/268338/average-math-score-overachieving-high-school-statistics-help?show=268359#a268359
<p style="text-align:justify">We need to find out whether 561 deviates significantly from the mean 517 to be considered exceptionally high. Work out the score (561-517)/118=0.3729 approximately. As a Z score this corresponds to 0.645, which means that 64.5% of SAT results would be below 561 and 35.5% would therefore be above 561. To be significant, we need only a small number of results to be higher than 561 (say, 5%) if we were to consider 561 to be exceptionally high. Even using the t-test with 55-1=54 degrees of freedom, we are nowhere near the critical value, so we can say with a reasonable degree of confidence that 561 is not significantly high enough to be considered exceptional, so the high school is not justified in its claim.</p>Statistics Answershttps://www.mathhomeworkanswers.org/268338/average-math-score-overachieving-high-school-statistics-help?show=268359#a268359Fri, 15 Nov 2019 10:13:21 +0000Answered: one tailed test, lower tail critical: degree of freedom=22 and t--2.92. WHat is the p-value?
https://www.mathhomeworkanswers.org/86005/tailed-test-lower-tail-critical-degree-freedom-what-the-value?show=268299#a268299
<p style="text-align: justify;">From tables a 1-tail test for 22 dof lies between 0.001 (3.505) and 0.005 (2.819).</p>
<p style="text-align: justify;">We can produce an approximate linear relationship between the probability p and the t-value.</p>
<p style="text-align: justify;">(2.819-3.505)/(0.005-0.001)=-171.5; p=-171.5t+c where c is a constant to find.</p>
<p style="text-align: justify;">Plug in (t,p)=(0.001,3.505): 3.505=-0.1715+c, c=3.6765.</p>
<p style="text-align: justify;">When p=2.92, 2.92=-171.5t+3.6765, t=0.7565/171.5=0.0044.</p>
<p style="text-align: justify;">The p-value is therefore 0.0044.</p>Statistics Answershttps://www.mathhomeworkanswers.org/86005/tailed-test-lower-tail-critical-degree-freedom-what-the-value?show=268299#a268299Wed, 13 Nov 2019 22:13:32 +0000Answered: two-tailed test with test statistic z=-2.25 and a=0.07, what is the P-value?
https://www.mathhomeworkanswers.org/55978/two-tailed-test-with-test-statistic-25-and-07-what-is-the-value?show=268298#a268298
<p style="text-align: justify;">Z=-2.25 is a p-value of 0.0122 compared to 0.07/2=0.035. So 0.0122 is more extreme than the critical significance level and H0 would be rejected.</p>Statistics Answershttps://www.mathhomeworkanswers.org/55978/two-tailed-test-with-test-statistic-25-and-07-what-is-the-value?show=268298#a268298Wed, 13 Nov 2019 21:43:15 +0000Answered: find the area between z=0 and z= -2.07
https://www.mathhomeworkanswers.org/268294/find-the-area-between-z-0-and-z-2-07?show=268297#a268297
<p style="text-align: justify;">Assuming normal distribution, N(0)=0.5 and N(-2.07)=0.019226, so N(0)-N(-2.07)=0.481 approx.</p>Statistics Answershttps://www.mathhomeworkanswers.org/268294/find-the-area-between-z-0-and-z-2-07?show=268297#a268297Wed, 13 Nov 2019 21:33:51 +0000Answered: which number could you remove from this list to make the mean and the median equal 2,7,12,14,17
https://www.mathhomeworkanswers.org/4924/which-number-could-remove-from-this-list-make-mean-median-equal?show=268103#a268103
<ol>
<li><span style="font-size:18px">7, 12, 14, 17: mean=50/4=12.5; median=(12+14)/2=13.</span></li>
<li><span style="font-size:18px">2, 12, 14, 17: mean=45/4=11.25; median=13.</span></li>
<li><span style="font-size:18px">2, 7, 14, 17: mean=40/4=10; median=(7+14)/2=10.5.</span></li>
<li><span style="font-size:18px">2, 7, 12, 17: mean=38/4=9.5; median=(7+12)/2=9.5.</span></li>
<li><span style="font-size:18px">2, 7, 12, 14: mean=35/4=8.75; median=9.5.</span></li>
</ol>
<p><span style="font-size:18px">You need to remove 14 for mean=median=9.5.</span></p>Statistics Answershttps://www.mathhomeworkanswers.org/4924/which-number-could-remove-from-this-list-make-mean-median-equal?show=268103#a268103Tue, 05 Nov 2019 23:00:51 +0000Answered: THIS DOSNT MAKE SENCE!!!
https://www.mathhomeworkanswers.org/268058/this-dosnt-make-sence?show=268072#a268072
<p style="text-align: justify;">“SO YOU ARE NOT RIGHT”</p>Statistics Answershttps://www.mathhomeworkanswers.org/268058/this-dosnt-make-sence?show=268072#a268072Tue, 05 Nov 2019 10:03:10 +0000Answered: Find the variance and standard deviation of 2,6,1,4,2,2,4,3,2
https://www.mathhomeworkanswers.org/71288/find-the-variance-and-standard-deviation-of-2-6-1-4-2-2-4-3-2?show=268017#a268017
<p><span style="font-family:.sfuitext; font-size:17pt"> x x-µ (x-µ)²</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 2 -8/9 64/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 6 28/9 784/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 1 -17/9 289/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 4 10/9 100/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 2 -8/9 64/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 2 -8/9 64/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 4 10/9 100/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 3 1/9 1/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> 2 -8/9 64/81</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">∑x/n=µ ∑(x-</span><span style="font-family:.sfuitext; font-size:17pt">)²/n=σ²</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">26/9 170/81=2.10 (variance)</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt"> √170/9=1.45 (standard deviation) (approx)</span></p>Statistics Answershttps://www.mathhomeworkanswers.org/71288/find-the-variance-and-standard-deviation-of-2-6-1-4-2-2-4-3-2?show=268017#a268017Mon, 04 Nov 2019 11:05:02 +0000Answered: how can i get the answer 33.333 by subtracting these numbers 123456789
https://www.mathhomeworkanswers.org/16509/how-can-get-the-answer-subtracting-these-numbers-123456789?show=267984#a267984
<p style="text-align:justify">Each number node in Figures 1 and 2 represents a column of two digits in the addition (or subtraction), so 1-4 represents the adjacent columns 1 to 4 in the arithmetic, either the first 4 columns or the last 4 columns for Type 1 or 2 respectively.</p>
<p><span style="font-size:16px">Figure 1:</span></p>
<p style="text-align:justify"><span style="font-size:16px"><img alt="" src="https://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=1987568112046544460" style="height:280px; width:500px"></span></p>
<p style="text-align:justify"><span style="font-size:16px">Figure 2:</span></p>
<p style="text-align:justify"><img alt="" src="https://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=4964627684524119046" style="height:367px; width:500px"></p>
<p style="text-align:justify"><span style="font-size:16px">Figure 3 :</span></p>
<p style="text-align:justify"><span style="font-size:16px"> <img alt="" src="https://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=1781705315270008296" style="height:260px; width:500px"></span></p>
<p style="text-align:justify"><span style="font-size:16px">Using letters to represent digits 1-9, there are two possible ways to do the arithmetic to get the difference 33.333:</span></p>
<p style="text-align:justify"><span style="font-size:16px">Type 1: RS.TU3-WX.YZ=33.333, which can also be written:</span></p>
<p style="text-align:justify"><span style="font-size:16px">RS.TU3=33.333+WX.YZ.</span></p>
<p style="text-align:justify"><span style="font-size:16px">Type 2: RS.TUV-W.XYZ=33.333, which can also be written:</span></p>
<p style="text-align:justify"><span style="font-size:16px">RS.TUV=33.333+W.XYZ.</span></p>
<p style="text-align:justify"><span style="font-size:16px">It is easier to solve the problem in addition form rather than subtraction.</span></p>
<p style="text-align:justify"><span style="font-size:16px">When adding two digits the sum may be less than 10, so there is no carryover.</span></p>
<p style="text-align:justify"><span style="font-size:16px">If the sum is greater than 10, there is a carryover of 1. This sum is a carryover donor.</span></p>
<p style="text-align:justify"><span style="font-size:16px">Also, the sum of two digits may need to include a carryover of 1 from the next column of figures (when there is one), and, another carryover may result from the sum. Therefore there are 4 classes of sums, designated by the letters A, B, C or D, as shown in the table in Figure 3. For example, 2+3=5, which is a Class A sum since no carryovers are involved. All cells containing A relate digit sums that similarly involve no carryover.</span></p>
<p style="text-align:justify"><span style="font-size:16px">Cells containing B show digit sums generating carryover (donors), for example, 8+3=11, relating 8 and 1.</span></p>
<p style="text-align:justify"><span style="font-size:16px">Cells containing C show digit sums including a carryover (acceptors) from the next column, for example 2+3+1 (carryover)=6, so 2 and 6 are related by Class C.</span></p>
<p style="text-align:justify"><span style="font-size:16px">And cells containing D show digit sums including a carryover from the next column and generating a carryover themselves, for example, 8+3+1=12, so 8 and 2 are related by Class D.</span></p>
<p style="text-align:justify"><span style="font-size:16px">So a sum donating a carryover must be adjacent to a sum accepting a carryover.</span></p>
<p style="text-align:justify"><span style="font-size:16px">This explains what’s going on in the trees in Figures 1 and 2. Figure 1 deals with Type 1 arithmetic while Figure 2 deals with Type 2 arithmetic. These trees show all the possible outcomes of the arithmetic in terms of classes.</span></p>
<p style="text-align:justify"><span style="font-size:16px">In Type 1 arithmetic, the last digit of the 5-digit number must be 3, while in Type 2 arithmetic the first digit (represented by the letter R) is either 3 or 4.</span></p>
<p style="text-align:justify"><span style="font-size:16px">Bear in mind that all digit assignments to the letters are unique so if 3 has been allocated a position no other letter can be assigned a value of 3. Similarly, for 4.</span></p>
<p style="text-align:justify"><span style="font-size:16px">The “leaves” of the trees form groups I call combos, which are unique combinations of classes. Taking each combo in turn and considering the sets of pairs of digits forming a class it’s now possible to search for a set of digits from 1-9 fitting a combo. The combo is eliminated if there are no valid digits.</span></p>
<p style="text-align:justify"><span style="font-size:16px">For example, the combo containing AAAA is not possible because each A requires a unique pair of digits from the set (see the class table in Figure 3), and Type 1 eliminates pairs containing 3 because 3 has already been allocated the last digit position in the 5-digit number. Type 2 eliminates pairs containing 3 or 4 depending on whether the lead digit is 3 or 4. So the set is reduced to { <a href="denied:tel:14 25 47 58 69" rel="nofollow">14 25 47 58 69</a> } or { <a href="denied:tel:25 36 58 69" rel="nofollow">25 36 58 69</a> } and neither set allows us to select 4 pairs containing unique digits. The best we can do is 3 pairs, for example, 14, 25, 69; 25, 47, 69; 14, 58, 69; 47, 58, 69.</span></p>
<p style="text-align:justify"><span style="font-size:16px">If we find a combo with a valid set of pairs, we have found a solution to the problem.</span></p>
<p style="text-align:justify"><span style="font-size:16px">We arrive at: 41.268-7.935=33.333 as one solution. Also, 41.286-7.953=33.333.</span></p>Statistics Answershttps://www.mathhomeworkanswers.org/16509/how-can-get-the-answer-subtracting-these-numbers-123456789?show=267984#a267984Sun, 03 Nov 2019 17:09:05 +0000Answered: Find the probability that the number of women employees in this sample of 20 that at least 5
https://www.mathhomeworkanswers.org/124547/find-probability-number-women-employees-sample-that-least?show=267903#a267903
idk. can i have money?Statistics Answershttps://www.mathhomeworkanswers.org/124547/find-probability-number-women-employees-sample-that-least?show=267903#a267903Fri, 01 Nov 2019 01:07:51 +0000Answered: suppose,X=5,5.8,Y=3,2.24,Z=0.185,_??find another value of z???
https://www.mathhomeworkanswers.org/91953/suppose-x-5-5-8-y-3-2-24-z-0-185-_-find-another-value-of-z?show=267834#a267834
Здесь вы можете заказать копию любого сайта под ключ, недорого и качественно, при этом не тратя свое время на различные программы и фриланс-сервисы. Клонированию подлежат сайты как на конструкторах, так и на движках: - Tilda (Тильда) - Wix (Викс) - Joomla (Джумла) - Wordpress (Вордпресс) - Bitrix (Битрикс) и т.д. телефон 8-996-725-20-75 звоните пишите viber watsapp Копируются не только одностраничные сайты на подобии Landing Page, но и многостраничные. Создается полная копия сайта и настраиваются формы для отправки заявок и сообщений. Кроме того, подключается админка (админ панель), позволяющая редактировать код сайта, изменять текст, загружать изображения и документы. Здесь вы получите весь комплекс услуг по копированию, разработке и продвижению сайта в Яндексе и Google. Хотите узнать сколько стоит сделать копию сайта? напишите нам 8-996-725-20-75 звоните пишите viber watsappStatistics Answershttps://www.mathhomeworkanswers.org/91953/suppose-x-5-5-8-y-3-2-24-z-0-185-_-find-another-value-of-z?show=267834#a267834Wed, 30 Oct 2019 20:19:50 +0000Answered: 3(3c − ) =2(c+1)
https://www.mathhomeworkanswers.org/267793/3-3c-%E2%88%92-2-c-1?show=267823#a267823
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">There seems to be a number missing after “3c-“ so we’ll represent the number by x and then try to find out what it could reasonably be.</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">3(3c-x)=2(c+1),</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">9c-3x=2c+2,</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">7c=3x+2.</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">If x=4:</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">7c=14 and c=2.</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">So if the equation had been:</span></p>
<p><span style="font-family:.sfuitext; font-size:17pt">3(3c-4)=2(c+1), then c=2.</span></p>
<p> </p>
<p> </p>Statistics Answershttps://www.mathhomeworkanswers.org/267793/3-3c-%E2%88%92-2-c-1?show=267823#a267823Wed, 30 Oct 2019 12:51:29 +0000Answered: What is the mean median and mode for 8, 125, 154,120,105, 125
https://www.mathhomeworkanswers.org/267800/what-is-the-mean-median-and-mode-for-8-125-154-120-105-125?show=267819#a267819
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">Order the data:</span></p>
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">8, 105, 120, 125, 125, 154.</span></p>
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">Mode is 125 (most repeated data).</span></p>
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">Sum of data: 637, size of data: 6, mean=637/6=106.2 (approx).</span></p>
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">Median is central datum, but, because there is no centre we take the average of the centre two: (120+125)/2=245/2=122.5.</span></p>
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">Mean=106.2, median=122.5, mode=125.</span></p>Statistics Answershttps://www.mathhomeworkanswers.org/267800/what-is-the-mean-median-and-mode-for-8-125-154-120-105-125?show=267819#a267819Wed, 30 Oct 2019 09:44:11 +0000Answered: What is the solution to this Statistic problem?
https://www.mathhomeworkanswers.org/267681/what-is-the-solution-to-this-statistic-problem?show=267684#a267684
<p style="text-align: justify;"><span style="font-family:.sfuitext; font-size:17pt">The probability of falling on tails is 0.7. The probability of this happening 6 times is (0.7)⁶=0.117649. All other outcomes include at least one head, and since all probabilities must sum to 1, the probability of at least one head=1-0.117649=0.882351, that is, 0.8824 to 4 decimal places.</span></p>Statistics Answershttps://www.mathhomeworkanswers.org/267681/what-is-the-solution-to-this-statistic-problem?show=267684#a267684Sun, 27 Oct 2019 08:48:01 +0000Normal Distribution
https://www.mathhomeworkanswers.org/267537/normal-distribution
<p><span style="font-family:times new roman,times,serif; font-size:medium">A manufacturer knows that their items have a normally distributed length, with a mean of 17.3 inches, and standard deviation of 2.1 inches.</span><br>
<br>
<span style="font-family:times new roman,times,serif; font-size:medium">If 12 items are chosen at random, what is the probability that their mean length is less than 16.1 inches?</span></p>
<p><span style="color:rgb(0, 0, 0); font-family:times new roman,times,serif; font-size:16.48px"><span style="font-family:mjxc-tex-math-i,mjxc-tex-math-ix,mjxc-tex-math-iw">P</span></span><span style="color:rgb(0, 0, 0); font-family:times new roman,times,serif; font-size:16.48px"><span style="font-family:mjxc-tex-main-r,mjxc-tex-main-rw">(</span><span style="font-family:mjxc-tex-main-r,mjxc-tex-main-rw">¯</span><span style="font-family:mjxc-tex-math-i,mjxc-tex-math-ix,mjxc-tex-math-iw">x</span><span style="font-family:mjxc-tex-main-r,mjxc-tex-main-rw"><</span><span style="font-family:mjxc-tex-main-r,mjxc-tex-main-rw">16.1</span><span style="font-family:mjxc-tex-main-r,mjxc-tex-main-rw">) = </span></span></p>
<p> </p>Statistics Answershttps://www.mathhomeworkanswers.org/267537/normal-distributionThu, 24 Oct 2019 07:31:03 +0000