I need ans

10+18+22+26+34=100
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question 2+6+14+18+22+26+30+34+83 =200  to in me kisi 5 ke 100 banao
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18+22+26+34+10-10=100... I.e 18+22+26+34+0=100..
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200-18-22-26-34
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There is no solution to this problem.

Lets see the explanation.

Explanation:

The given sequence is in A.P with initial term, a=2 and common difference, d=4.

So the numbers are 2+4n1, 2+ 4n2, 2+4n3, and so on.

Now we need to add any 5 nos. in order to get total as 100.

Lets say these nos are 2+4n1, 2+4n2, 2+4n3, 2+4n4, 2+4n5.( Or for that matter u can take randomly as n7, n3, etc)

Now lets add these nos. and as we now sum should be 100,

Therefore, we have

(2+4n1) + (2+4n2) +  (2+4n3) +  (2+4n4) + (2+4n5) = 100

4( n1 + n2 + n3 + n4 + n5 ) + 10 = 100

4( n1 + n2 + n3 + n4 + n5 ) = 90

n1 + n2 + n3 + n4 + n5 = 90/4

Since 90 is not completely divisible by 4, we can conclude that there is no solution to the above problem.

Hence the proof.
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2+6+10+14+18+22+26+30+34+38                 from this which five digits can make a total of 100 only through addition
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200-38-34-30+2=100
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(6+10)*2+30+38 = 16*2+68 = 32+68 = 100
(26+30)/2+34+38 = 56/2+72 = 28+72 = 100

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THIS ANSWER IS NOT POSSIBLE NO MATTER HOW EVER YOU TAKE AND ADD THE NUMBERS YOUR ANS WILL BE IN EITHER 4 NO'S OR 6 NO'S ITS NOT POSSIBLE TO GET A 100 USING 5 NO'S. ACTUALLY THE FIRST FOUR NUMBERS ARE A TETRAMETHYLHEXADECANE A CHEMISTRY STRUCTURAL FORMULA
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guyz finally i got ri8 ans its 18+22+30+26+2^2=100
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The series is in arithmetic progression where the universal formula for AP can be applied as S = n/2 {2a + (n â€“ 1) d}, the symbols being â€˜Sâ€™ = sum; â€˜aâ€™ = first term; â€˜dâ€™ = common difference; â€˜nâ€™ = no. of terms Here, â€˜aâ€™ = 2 â€˜dâ€™ = 4 â€˜nâ€™ = 10 Thus with the formula for AP, â€˜Sâ€™ = 200 Now, the condition depicted in the question is that â€˜Sâ€™ would be 100 when â€˜nâ€™ = 5 and â€˜dâ€™ = 4. â€˜aâ€™ is to be determined. Ok, we are required to put the values in the formula S = n/2 {2a + (n â€“ 1) d}. 100 = 5/2[{2a + {(5 â€“ 1) * 4}] â†’ 100 = 5/2{ 2a + (4 * 4)} â†’ 100 = 5/2(2a +16) â†’ 100 = 5/2 *2 (a + 8) = 5(a + 8) â†’ 20 = a + 8 â†’ a = 20 â€“ 8 = 12 To fulfill the condition first term is required to be 12 and other four terms would be 16; 20; 24; 28. None of this series is within the given series starting with 2. Evident that nos. available with the given series (any five), sum cannot be 100.
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(10+14)*2+22+30. =100
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22+18+34+16+10
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by Level 4 User (5.6k points)

{14+6}x2+{34+26)
20x2 + 60.
40 + 60 = 100.

by Level 1 User (140 points)
20+20+20+20+20
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6+10+22+28+34=100....
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200 - 38 - 34 - 30 + 2 = 100 Question is completely saying total which means addition as well as distraction
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200 - 38 - 34 - 30 + 2 = 100 Question is saying total N total means addition as well as substraction. So here is d answer
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5 number use karke 100 ban sakta hey, 5 number ka total karne pe nahi banta...............
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30+34+38+6+14-22=100

adding 5 no's they said not substract so i added 5 no's out of 10 no's and i substract 1 no. in the given 10 no's

so i think this is only the way you will get 100
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2+6+10+14+18+22+26+30+34+38=200 LOL

SO 200-38-34-30+2=100

by Level 9 User (42k points)

6+10+22+28+34 = 100

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Add the #'s together and you get 100. Is it really that hard? I've heard Pre-Calculus is hard. My older brother is taking Pre-Cal and he says it hurts so bad! LOL! My brother is in college now and his Pre-Cal teacher is so awesome. Anyways. The answer is 100

by Level 2 User (1.4k points)